tag:blogger.com,1999:blog-35187314.post6940807011822796024..comments2018-01-19T09:05:52.126-05:00Comments on Physics Buzz: Ask a Physicist: Time DilationBuzz Skylinehttp://www.blogger.com/profile/04255849304022062681noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-35187314.post-77182358725988726702017-12-23T12:56:32.971-05:002017-12-23T12:56:32.971-05:00This is an explanation, but a graph at the end wou...This is an explanation, but a graph at the end would have gone some way toward answering the question.<br /><br />Also, a small quibble; the train's pitch would "seem" higher because it would actually be higher.Unknownhttps://www.blogger.com/profile/08630589147483611327noreply@blogger.comtag:blogger.com,1999:blog-35187314.post-19637944854047118352017-12-23T07:51:50.318-05:002017-12-23T07:51:50.318-05:00"Time passes slower for you the faster you mo..."Time passes slower for you the faster you move" is not a correct statement because all inertial frames are equivalent. If you are in an inertial frame (not accelerating), everything in that frame, that is, moving at the same velocity as you, will experience the same time. Time as observed by you in any frame moving relative to yours will appear slower as you measure it. Your own inertial frame is always at zero velocity. All other frames will be moving away from you with velocities pointing outward around a sphere, and you will see the time dilation as described in this article for them, for any mirror placed along the perpendicular from the point of measurement in your frame to the relative velocity vector in the other frame. Only through acceleration of your own frame can you break the symmetry. A more correct statement would be: "You will observe more time dilation between your own frame and and any other frame if you accelerate away from it." Consequently you will observe less time dilation on the frames you accelerate towards, that is, frames for which you reduce your relative velocity. randall morrishttps://www.blogger.com/profile/03386204823312684519noreply@blogger.comtag:blogger.com,1999:blog-35187314.post-15432380484931200942017-12-22T13:07:11.049-05:002017-12-22T13:07:11.049-05:00You can do it through trig too: just use cos(arcsi...You can do it through trig too: just use cos(arcsin(v)) using speed units where c=1. E.g. 0.866c is the speed that gives you length contraction to half the rest length and makes clocks tick at half their rest rate. For a full understanding of this, see http://www.magicschoolbook.com/science/relativity.htmlDavid Cooperhttps://www.blogger.com/profile/00790590490778489701noreply@blogger.com