tag:blogger.com,1999:blog-35187314.post5301624557446735828..comments2020-10-19T07:48:40.816-04:00Comments on Physics Buzz: Olympic Women Ski Jump Equally Far on the MoonAPS Webmasterhttp://www.blogger.com/profile/05951833208918853453noreply@blogger.comBlogger6125tag:blogger.com,1999:blog-35187314.post-60476128299518212852014-02-12T19:42:05.105-05:002014-02-12T19:42:05.105-05:00This blog relates to what I'm currently learni...This blog relates to what I'm currently learning in my physics class. I feel that as long as the ratios are correct this makes perfect sense. Air pressure and velocity would need to have the same impact on the skier in order for the distance to be the same. We see on earth air resistance would effect the skier in both a positive way. While air resistance would not be a factor on the moon, having a slower velocity if equal to the effect of air resistance on earth could cause the skier to land in exactly the same distance on both the moon and the earth. - Jake LawrenceAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-35187314.post-36196339707546588072014-02-12T18:49:02.101-05:002014-02-12T18:49:02.101-05:00Retracting previous comments. The solution here is...Retracting previous comments. The solution here is fine, as I'm sure the author already knows... :) The ratios dvy_e/dvy_m and v_e/v_m definitely are equal though they are solved for differently.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-35187314.post-71748278898826294472014-02-12T17:49:20.837-05:002014-02-12T17:49:20.837-05:00I think the error in the solution presented is in ...I think the error in the solution presented is in the ratio used for dv_e/dv_m. It assumes the same energy conservation relations used to solve for v_e/v_m, which is incorrect because one now needs to include kinetic energy for the initial energy after the ramp. I would keep everything else in the solution the same and replace with the relation dv_e/dv_m >= sqrt(g_e/g_m). (It comes from energy conservation, with initial kinetic energy, and the triangle inequality (dv)^2 >= v_f^2 - v_0^2 = 2g_eh.) The '=' in this relation is for the case that v_e,v_m=0 and leads to them flying the same distance. All other cases (v_e, v_m not equal 0, which is what we have) lead to traveling a greater distance on earth!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-35187314.post-57394426924875805322014-02-12T17:33:27.170-05:002014-02-12T17:33:27.170-05:00This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/16954145630452998730noreply@blogger.comtag:blogger.com,1999:blog-35187314.post-59833040539828212202014-02-12T16:50:18.819-05:002014-02-12T16:50:18.819-05:00This is great idea to write about, but there's...This is great idea to write about, but there's one error in your ideal case solution (i.e. no air resistance) that is a little disappointing. Everything is ok until you start to solve for the time spent in the air after the ramp. Solve for the ratio of these time explicitly, assuming the distance fallen after jump is the same on earth and the moon and using the velocities already solve for, and you'll get a very different answerAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-35187314.post-61765152557866094062014-02-11T20:41:34.384-05:002014-02-11T20:41:34.384-05:00This blog post is not only relevant to current eve...This blog post is not only relevant to current events but to the introduction to physics class I am currently in. It is discussed here that velocity, time, distance, and gravity are important to get to the 95 meter mark, or further. Air resistance and gravity are important for this problem if it occurs on Earth. The air resistance could create a force against the skier and slow the velocity at which she is falling. Some have experienced this themselves when skiing and going off a jump. Since this problem is calculated on the moon where air resistance and gravity are not a factor it becomes easier to calculate. We learned that air resistance is not always a significant enough factor to calculate in, but in this case it happens to be necessary for a more accurate answer. Anonymousnoreply@blogger.com